prove that 3+√2 is an irrtional number
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Answer:
Step-by-step explanation:
Before proving thus let take root 2 be a rational number and then it can be written in a by b form
Therefore root 2 is equal to a by b.
Now square both sides
Then you will get 2 is equal to a² by b².
Then take b² towards the left means towards 2.
This will give us that a² is factor of root 2
Similarly b² is also factor of root 2
Therefore root 2 has more then
1 factors therefore our consumption went wrong
Therefore root is irrational number
Now according to question 3+ root 2..
Let it be also rational number
Then it can be written in form of a by b
Therefore move 3 to that side and see what you get
Whatever we get at one side there would be root 2 and on other side a rational number.. .....
Therfore we know that root 2 is irrational therefore our consumption again went wrong
Therefore 3 + root 2 is also an irrational number.....
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