Prove that √3 - √2 is irrational
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Let us assume that√3 -√2 is rational number.
So, it can be written in the form of P/Q
=> √3 - √2 = p/q
Squaring both sides
=> (√3 -√2)² = (p/q)²
√3² +√2² -2 × √3 × √2 = p²/q²
3+2-2√6 = p²/q²
5 -2 √6 =p²/q²
2√6 =5-p²/q²
2√6 = (5q² - p²)/q²
√6 = (5q² - p²)/2q²
p & q are integers and (5q² -p²)/2q² is rational number.
But √6 is irrational number
So, this contradicts that √6 is irrational number.
Our assumption is incorrect.
√3 -√2 is irrational number
Hence Proved
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