Prove that ³√2 is irrational.
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Assume
![\sqrt[3]{2}](https://tex.z-dn.net/?f=+%5Csqrt%5B3%5D%7B2%7D+ "\sqrt[3]{2}")
be rational
so
![\sqrt[3]{2} = \frac{a}{b}](https://tex.z-dn.net/?f=+%5Csqrt%5B3%5D%7B2%7D++%3D++%5Cfrac%7Ba%7D%7Bb%7D++ "\sqrt[3]{2} = \frac{a}{b}")
where a and b are coprimes and b not equal to zero
squaring
be rational
so
where a and b are coprimes and b not equal to zero
squaring
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