Prove that √3 + √2 is irrational.
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Answer:
Let √3 - √2 be a rational number , say r
Then √3 - √2 = r
On squaring both sides we have
(√3 - √2)2 = r2
3 - 2 √6 + 2 = r2
5 - 2 √6 = r2
-2 √6 = r2 - 5
√6 = - (r2 - 5) / 2
Now - (r2 - 5) / 2 is a rational number and √6 is an irrational number .
Since a rational number cannot be equal to an irrational number . Our assumption that
√3 - √2 is rational is wrong
Answered by
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Answer:
√3+√2 = p/q
√3 =p/q - √2
√3 = p - √2q / q
So, √3 + √2
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