Question

prove that 3√2 is irrational​

Answer 1

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Answer 2

Let us assume, to the contrary, that 3√2 is rational.Then, there exist co-prime positive integers a and b such that

3√2=a/b

=>√2=a/3b

=>√2 is rational (∵3,a and b are integers)

Therefore,a/3b is a rational number

This contradicts the fact that √2 is irrational.

So, our assumption is not correct.

Hence, 3√2 is an irrational number.