Prove that 3 - √2 is irrational
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3+√2 = a/b ,where a and b are integers and b is not equal to zero .. therefore, √2 = (3b - a)/b is rational as a, b and 3 are integers.. ... So, it concludes that 3+√2 is irrational
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Let √3 - √2 be a rational number , say r
Then √3 - √2 = r
On squaring both sides we have
(√3 - √2)2 = r2
3 - 2 √6 + 2 = r2
5 - 2 √6 = r2
-2 √6 = r2 - 5
√6 = - (r2 - 5) / 2
Now - (r2 - 5) / 2 is a rational number and √6 is an irrational number .
Since a rational number cannot be equal to an irrational number . Our assumption that
√3 - √2 is rational is wrong
hope this helps you
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