Prove that √√3+√√2 is irrational.
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Answer:
it is irrational
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Answered by
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Answer:
let the no. is rational so we can write it in the form of p/q where p and q are co primes and p is not equals to 0
root 3+2=p/q
root 3 =p/q-2
let root 3 is rational
(root 3) square =(a/b)square
3b square=a square
a square is divisible by 3
a is also " " " " ""
let a= 3c
3b square =9c square
b square=3c square
b square is divisible by 3
b is also divisible by 3
this contradicts the fact that our assumption is wrong so under root 3 is irrational
so irrational is not equals to rational so
is an irrational no.
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