Math, asked by kpavar882, 1 month ago

prove that 3√2 is irrational

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Answered by csingh296parihar
2

3+√2 = a/b ,where a and b are integers and b is not equal to zero .. therefore, √2 = (3b - a)/b is rational as a, b and 3 are integers.. ... So, it concludes that 3+√2 is irrational

so that's how it's proves

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Answered by ᏢerfectlyShine
6

Answer:

3+√2 = a/b ,where a and b are integers and b is not equal to zero .. therefore, √2 = (3b - a)/b is rational as a, b and 3 are integers.So, it concludes that 3+√2 is irrational..

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