Question

Prove that 3√2 is irrational number.
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Answer 1

Answer:

Answer. 3+√2 = a/b ,where a and b are integers and b is not equal to zero .. therefore, √2 = (3b - a)/b is rational as a, b and 3 are integers.. ... So, it concludes that 3+√2 is irrational..

Answer 2

Answer:

As we know that the definition of irrational number. That number which is in root is called irrational number. A irrational number is real number but all real number is not irrational number. 3√2 is a irrational number. but 3√4 is not a irrational number . it is a rational number