prove that 3-2 root 5 is irrational number
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Answered by
19
Answer:
Step-by-step explanation:
3 - 2√5 = a/ b
-2√5 =a/b -3
√5 =a-3b/-2b
√5 is rational.
This contradicta the fact that √5 is irrational.
So our supposition is incorrect.
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Step-by-step explanation:
3 - 2√5 = a/ b
-2√5 =a/b -3
√5 =a-3b/-2b
√5 is rational.
This contradicta the fact that √5 is irrational.
So our supposition is incorrect.
KEEP CALM
AND
SUPPORT
MATE'S
vanshikayadav2126:
it is 3-2√ 5 not 3+2√ 5
Answered by
21
so this is from chapter real numbers
let us suppose that 3-2√ 5 is a rational number
that means
3-2√ 5 = p/q where p and q are integers and co prime
-2√ 5 = p/q-3
-2√ 5 = p-3q/q
√ 5 = p-3q/-2q (cross multiplying)
but √ 5 is an irrational number
=> that p-3q/-2q is also irrational
this contradicts our assumption that 3-2√ 5 is rational
=> 3-2√ 5 is irrational
hence.proved.
Hope this helps!
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