Prove that 3 + 2 root 5 whole square is irrational
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Answered by
71
Answer:
(3+2root 5)^2 =(3)^2 +(2root5) ^2 +2.3.2root5
=9+20+12root5
=29+root720(because root720 is irrational no. so whole no. is irrational)
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Step-by-step explanation:
Answered by
119
Answer:
To Prove : (3 + 2√5)² is irrational No.
First we simplify using identity, (a+b)² = a² + 2ab + b²
(3 + 2√5)² = 3² + (2√5)² + 2×3×2√5
= 9 + 4×5 + 12√5
= 29 + 12√5
we use the result that √5 is an irrational no.
we know that product of rational and irrational no is and irrational no.
⇒ 12 × √5 = 12√5 is an irrational no.
Now, Addition of a rational no with irrational given an irrational no.
⇒ 29 + 12√5 is an irrational no.
since, 29 + 12√5 = (3 + 2√5)²
⇒ (3 + 2√5)² is an irrational .
Hence Proved
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