Question

prove that 3(√2a)(2b)(-3c) = 18√2abc​

Answer 1

Question -

2√2a^3+8b^3-27c^3+18√2abc

Answer :-

=>2√2a³+8b³-27c³+18√2abc

=>(√2a)³+(2b)³+(-3c)³-3(√2a)(2b)(-3c)

=>(√2a+2b-3c)(2a²+4b²+9c²-2√2ab+6bc+3√2ca)

Thank you! ❤

Answer 2

Answer:

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