prove that 3√2by 5 is a irrational number
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- 3√2/5 is no
- It is irrational
Let 3√2/5 is a rational no
Then
it must be exsist in a/b where b. is not equal to 0
3√2/5=a/b
=>3√2/5=a/b
=>3√2=5a/b
=>√2 = 5a/2b
Here 5a/2b is a rational no therefore √2 be also rational
- But we know that √2 is a irrational no
- So our assumption is wronge
- Therefore 3√2/5 is a irrational no
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