Math, asked by devrajjinger4235, 1 month ago

Prove that 3-2root5 is irrational.​

Answers

Answered by Bhageeradh
0

Answer:

Step-by-step explanation:

Let us assume that 3 + 2√5 is a rational number.

So, it can be written in the form a/b

3 + 2√5 = a/b

Here a and b are coprime numbers and b ≠ 0

Solving 3 + 2√5 = a/b we get,

=>2√5 = a/b – 3

=>2√5 = (a-3b)/b

=>√5 = (a-3b)/2b

This shows (a-3b)/2b is a rational number. But we know that √5 is an irrational number.

So, it contradicts our assumption. Our assumption of 3 + 2√5 is a rational number is incorrect.

3 + 2√5 is an irrational number

Hence proved

Answered by yashikaagrawalixe
0

Answer:

See the attachment

This is the solution for 3 +2√5. You can just change the signs everywhere and use this solution.

Hope it helps you!

Attachments:
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