Math, asked by meenakshymanoj4, 5 months ago

prove that √3+3÷√2 is irrational​

Answers

Answered by vansh2103
1

Answer:

 \frac{ \sqrt{3} + 3 }{ \sqrt{2} }  =  \frac{ \sqrt{3} + 3 }{ \sqrt{2} }  \times  \frac{ \sqrt{2} }{ \sqrt{2} }  \\  =  \frac{ \sqrt{6}  + 3 \sqrt{2} }{2}  \\ clearly \:  \frac{ \sqrt{ 6} + 3 \sqrt{2}  }{2} is \: irrational \\  and \: 2 \: is \: rational \\ and \:  \frac{irrational}{rational}  = irrational \\ thus \:  \sqrt{3}  + 3 \div 2is \: irrational

Answered by s13397adisha2258
61

Answer:

Answer:

Gudie Evening

Explanation:

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Step-by-step explanation:

answer:-3/2√3

=√9/√12

=√(9/12)

=√(3/4)

=√3/2

√3/2 is irrational therefore 3/2√3 is irrational

☆Thus proven,☆

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