Question

prove that √3+3÷√2 is irrational​

Answer 1

Answer:

$\frac{ \sqrt{3} + 3 }{ \sqrt{2} } = \frac{ \sqrt{3} + 3 }{ \sqrt{2} } \times \frac{ \sqrt{2} }{ \sqrt{2} } \\ = \frac{ \sqrt{6} + 3 \sqrt{2} }{2} \\ clearly \: \frac{ \sqrt{ 6} + 3 \sqrt{2} }{2} is \: irrational \\ and \: 2 \: is \: rational \\ and \: \frac{irrational}{rational} = irrational \\ thus \: \sqrt{3} + 3 \div 2is \: irrational$

Answer 2

Answer:

Answer:

Gudie Evening

Explanation:

${❥Sachuuu❣</p><p>❥Sachuuu❣$

Step-by-step explanation:

answer:-3/2√3

=√9/√12

=√(9/12)

=√(3/4)

=√3/2

√3/2 is irrational therefore 3/2√3 is irrational

☆Thus proven,☆