Question

Prove that 3+3√5 iss irrational. ​

Answer 1

Answer:

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Step-by-step explanation:

Let us assume that 3+5 is a rational number.

Now,

3+5=ba [Here a and b are co-prime numbers]

5=[(ba)−3]

5=[(ba−3b)]

Here, [(ba−3b)] is a rational number.

But we know that 5 is an irrational number.

So, [(ba−3b)] is also a irrational number.

So, our assumption is wrong.

3+5 is an irrational number.

Hence, proved.

Answer 2

Step-by-step explanation:

Let us assume 3+3root 5 is a rational number.

3+3root5=a/b

3+a/b= -3root5

3b+a/-3b=root 5

but root 5 is an irrational number.

So our assumption is contradicts 3+3root5 is an irrational number.

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