Question

prove that: 3^-3 × 6^2 × √98 ÷ 5^2 × 3√1/25 × (15)^-4/3 × 3^1/3 = 28√2

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

given : $3^{-2} * 6^{2} * \sqrt{98} / 5^{2} * 3\sqrt{1 / 25} * 15^{-4/3} * 3^{ 1 / 3}$

find : LHS = RHS

Solution:

$LHS = \frac{ (1 / 27) * 36 * 7\sqrt{2} * 5^{2 / 3} * (5 ^ {4 / 3} * 3 ^ {4 / 3}) }{ \sqrt[3]{3} * 1 * 5^{2} }\\= > \frac{4 * 7 \sqrt{2} * 5 ^ {2+4 / 3} * 3 ^ {3 / 3}}{5 ^ {2} * 3}\\= > \frac{28 \sqrt{2} * 5 ^{2} * 3 }{ 5^2 * 3}\\ = > 28\sqrt2$

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