Prove that (3, 3), (6, 6) and (−2 , −2) are collinear points.
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If Δ=0, the points are collinear
Area of triangle=
Δ=1/2|x1(y2-y3)+x2(y3-y1)+x3(y1-y2)|
Δ=1/2|3(6-(-2))+6(-2-3)+(-2)(3-6)|
Δ=1/2|3(8)+6(-5)-2(-3)|
Δ=1/2|24-30+6|
Δ=1/2×0
Δ=0, the points are collinear
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