prove that 3+3=7
i mark u as brainliest
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let a=b where a=3, b=7
a=b
a(a=b)---------multiply a
a^2=ab----------distribute
-(b^2)+(a^2=ab)---------add -(b^2)
a^2-b^2=ab-b^2-------addition property
(a-b)(a+b)=b(a-b)-------factor
a+b=b---------substitute since a=b
a+a=b
3+3=7
please mark as brainliest
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