prove that 3-√3 is irrational
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Answer:
Therefore there exists no rational number r such that r2=3. Hence the root of 3 is an irrational number.
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Answered by
0
Step-by-step explanation:
Therefore there exists no rational number r such that r2=3. Hence the root of 3 is an irrational number.
...
Thank you
Let us assume that 3−
3
is a rational number
Then. there exist coprime integers p, q,q
=0 such that
3−
3
=
q
p
=>
3
=3−
q
p
Here, 3−
q
p
is a rational number, but
3
- is an irrational number.
But, an irrational cannot be equal to a rational number.This is a contradiction.
Thus, our assumption is wrong.
Therefore 3−
3
is an irrational number
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