prove that 3+4√5 is an irrational number
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Answered by
1
Answer:
Let us assume that 3+4√5 is a rational number
Therefore 3+4√5=a/b where a and b are coprime's and b not equal to 0
4√5 =a/b-3
4√5 =a-3b/b
√5 =a-3b/4b
therefore a-3b/4b is in the form a/b which is a rational number.
But this is contradicts the fact is that √5 is irrational number.
Therefore, our assumption is wrong and 3+4√5 is an irrational number.
Hope this answer helps you.
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