Question

prove that 3+4root5 is an irrational number
$3 + 4 \sqrt{5}$
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Answer 1

Answer:

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Answer 2

→ let take that 3+2 √5

is rational number

→ so, we can write this answer as

⇒3+2√5=a÷b

Here a & b use two coprime number and b=0

⇒2 √5

=a÷b-3

−3

⇒2 √5 = a-3b÷b

√5=a-3b÷2b

Here a and b are integer so

a−3b÷2b

There our assumption is wrong

- Hence 3+2 √5

is irrational number.