Question

prove that 3√5-2 is an irrational number​

Answer 1

Answer:

Assume that 3√5−2 is rational 3√5−2 = a/b where a and b are co- prime integers 3√5 = a - 2b / b √5= a- 2b / 3b

RHS is of the form p/q therefore,LHS is also rational.but it contradicts the fact that root 5 is irrational due to our incorrect assumption that 3√5-2 is rational, hence 3√5-2 is irrational