Question

Prove that 3√5-7 is an irrational number. ​

Answer 1

Answer:

Step-by-step explanation:

since root 5 = an irrational numeral

the whole number is multiplied to it and hence it an irrational number.

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Answer 2

3√5-7=a/b

3√5= a/b+7

√5 = a+7b/3b

Hence proved....