Question

prove that 3-√5/7 is irrational number
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Answer 1

Answer:

Step-by-step explanation:

Let us assume to the contrary that 3√5-7 is a rational no.

Such That ,

3√5-7=p/q {where, p and q are integers having no common factors}.

3√5=p/q+7

3√5=.p+7q/q

√5= p+7q/3q

where , √5 and p+7q/3q are rational numbers.

But this contradicts the fact that √5 is irrational.

Therefore,3√5-7 is an irrational no.

Answer 2

Here Is Your Ans ⤵

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Let 3 - √5 / 7 is an rational number

➡3 - √5 / 7 = A / B

➡- √5 / 7 = A / B - 3

➡- √5 = 7A / B - 3

➡√5 = - 7A / B - 3

Integer = Fraction

So , Our assumptions is Wrong

3 - √5 / 7 is an irrational Number

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