Question

prove that√3+√5 an irrational no's​

Answer 1

because it has no denominator hence it is not rational or irrational

Answer 2

Let's assume √3+√5 to be a rational no.

(√3+√5)^2 also must be rational

(√3+√5)^2 = (√3)^2 + (√5)^2 + 2(√3*√5)

(√3+√5)^2 = 3 + 5 + 2√15

(√3+√5)^2 = 8 + 2√15

8 + 2√15 is irrational...

This is because the sum of a rational and irrational number is always irrational.

If (√3+√5)^2 is irrational...

√3+√5 also must be irrational

Therefore, √3+√5 is irrational.

Hope it helps

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