Prove that √3+√5 is a irrational number.
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Answered by
7
Let √ 3 + √ 5 be rational
√ 3 + √5 = P/q
(√3 +√5) sq=(P/q)sq
3 +5 + 2 √15 = P²/q²
√ I5 = (P² / q² -7) 1/2
RHS is rational as all are integers
⇒ LHS is also rational but √ 15 is irrational
⇒ √3 + √ 5 is irrational
Answered by
1
Answer:
in the attachment u can understand easily
root15 you can see it is in the p by q
but we know that root15 is an irrational number
so our contradiction is wrong
therefore the given number is an irrational number
plz mark as brainliest
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