Question

prove that 3+√5 is an irrational number​

Answer 1

Answer:

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3+√5

let us assume that 3+root5 is rational

a and b are co primes

and b is not equal to 0

3+√5 = a divided by b

3-a by b=√5

rearrange

√5=-a divided by b = 3b+a divided by b

3b+a by b is rational

and √5 is irrational

hence contradiction is wrong 3+√5 is irrational

hope helps

Answer 2

Step-by-step explanation:

To prove that 3+root5 is an irrational number :

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