Question

prove that 3+ √5 is an irrational number​

Answer 1

Answer:

let 3+√5 is rational

it can be written in the form of a and b

3+√5 =a/b

√5=a/b-5

a-5b=√5

therefore √5 is rational

but our assumption is wrong

√5 is irrational

hence proved

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Answer 2

Answer:

We have 3+root 5

So let it be a rational no.

Now it is in the form of

3+root5=a/b

Hence

A/b-3=root 5

And root 5=a-3b

Hence root 5 is a irrational no.

Because we may not be write root 5 in the form of rational no.