prove that 3+ √5 is an irrational number
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Answered by
1
Answer:
let 3+√5 is rational
it can be written in the form of a and b
3+√5 =a/b
√5=a/b-5
a-5b=√5
therefore √5 is rational
but our assumption is wrong
√5 is irrational
hence proved
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Answered by
0
Answer:
We have 3+root 5
So let it be a rational no.
Now it is in the form of
3+root5=a/b
Hence
A/b-3=root 5
And root 5=a-3b
Hence root 5 is a irrational no.
Because we may not be write root 5 in the form of rational no.
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