Question

prove that 3+√5 is an irrational number​

Answer 1

Answer:

As √5 is a irrational number . If you add any rational number it will irrational only

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

let us assume that 3+root 5 is a rational number,

Now,

3+root 5=a/b

root5=(a/b-3)

root5=(a-3b/b)

Hence{(a-3b/b}) is a rational number

but we know that root5 is an irrational number

so,{(a-3b/b)} is also a irrational number

so,our assumption is wrong

3+root 4 is an irrational number

HENCE PROVED

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