Question

prove that 3+√5 is an irrational number​

Answer 1

Answer:

Let us assume that 3+

5

is a rational number.

Now,

3+

5

=

b

a

[Here a and b are co-prime numbers]

5

=[(

b

a

)−3]

5

=[(

b

a−3b

)]

Here, [(

b

a−3b

)] is a rational number.

But we know that

5

is an irrational number.

So, [(

b

a−3b

)] is also a irrational number.

So, our assumption is wrong.

3+

5

is an irrational number.

Hence, proved.

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Answer 2

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