prove that 3+√5 is an irrational number
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⇒ 3 + 5 = p q , where p and q are the integers and q ≠0. Since p , q and 3 are integers. ... This contradiction has arisen due to the wrong assumption that is a rational number. Hence, is an irrational number.
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Answer:
let 3+✓5 be a rational number.
so , 3+✓5=a/b
✓5=a/b-3
so , this implies that 3+✓5 is a rational number .
but , ✓3 is a irrational number
therefore , our assumption is wrong
so , 3+✓5 is a irrational number
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