Prove that √3+√5 is an irrational number.
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Answered by
6
Let root 3 + roof 5 be rational
root 3 + root 5 = P/q
(root 3 + root 5) sq=(P/q)sq
3 +5 + 2 root 15 = P sq/q Sq
root I5 = (Psq / qsq -7) 1/2
RHS is rational as all are integers
⇒ LHS is also rational but root 15 is irrational
⇒ root3 + root 5 is irrational
Anonymous:
Dude how 3+5+2 came??
squaring (root3 + root5) = 3+5+ 2*root15
I am not getting the answer bro!!!
sunn bhai (√3+√5)^2 = (√3)^2 + (√5)^2 + 2*√15=3+5+2√15
Answered by
2
First prove √3 or √5 is in ur own method and conclude that any number added to a irrational in irrational
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