prove that 3 + √5 is an irrational number
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Here is your answer....☺
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→ Let 3 + √5 = a/b [ A form of a rational number]
=> √5 = a/b - 3
=> √5 = a - 3b/b
Hence, in LHS we have an irrational number and in RHS we obtained a rational number .
Hence, our assumption is wrong.
→ 3 + √5 is an irrational number.
Proved!!
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Hope this helps you...☺
Thanks...☺
Here is your answer....☺
================================
→ Let 3 + √5 = a/b [ A form of a rational number]
=> √5 = a/b - 3
=> √5 = a - 3b/b
Hence, in LHS we have an irrational number and in RHS we obtained a rational number .
Hence, our assumption is wrong.
→ 3 + √5 is an irrational number.
Proved!!
=================================
Hope this helps you...☺
Thanks...☺
Vadaliya:
thanks
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