Question

Prove that √3+√5 is an irrational number?
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Answer 1

Answer:

Step-by-step explanation:

let root 3 + roof 5 be rational

root 3 + root 5 = P/q  

(root 3 + root 5) sq=(P/q)sq  

3 +5 + 2 root 15 = P sq/q Sq  

root I5 = (Psq / qsq -7) 1/2  

RHS is rational as all are integers

⇒ LHS is also rational but root 15 is irrational  

⇒ root3 + root 5 is irrational

hope it helps.