Math, asked by gunmaypachauri, 19 days ago

Prove that 3 + √5 is an irrational number.​

Answers

Answered by Anonymous
2

Answer:

3 + √5 = p q , where p and q are the integers and q ≠0. Since p , q and 3 are integers. So, p - 3 q q is a rational number. ... Hence, is an irrational number.

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Answered by Anonymous
4

Answer:

as \: we \: know \: that \:  \sqrt{5}  \: is \: an \: irrational \\ number \: also \: sum \: of \: an \: irrational \\and \: rational \: number \: is \: always \\ irrational \: and \: also \: 3 \: is \: a \\ rational \: number \\ hence \: 3 +  \sqrt{5} \:   is \: an \: irrational \: number \: \\  \\  \\ hence \: proved

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