Prove that 3+√5 is an irrational number.
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Let 3 + √5 Is an rational number
➡3 + √5 = A / B
➡√5 = A / B - 3
➡√5 = A - 3B / B
Irrational = Rational
So , our assumptions is incorrect ,3 + √5 is an irrational number
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hey mate!
here is your answer:
step by step explanation:
We know , that root 5 is irrational .
Let us assume that 3+root 5 is rational and 3+root 5 =a/b ,where a and b are two co primes.
Now, 3+ root 5 =a/b
root 5 = a/b-3
root 5 = a-3b/b
We know, that root 5 is irrational so, a-3b/b should also be irrational. But this contradicts our assumption that 3+root 5 is rational.
Thus , 3+root 5 is irrational.
hope it helped^_^
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