Question

Prove that 3+√5 is an irratoinal number with full explanation.


-SPAM AND COPIED ANSWER WILL NOT BE ACCEPTED AND WILL BE REPORTED STRAIGHT


$\boxed{\mathfrak\red{Thankyou!}}$

​

Answer 1

Answer:

Your Question :-

Prove that 3+√5 is an irratoinal number with full explanation.

Solution:-

Let us assume , that 3+√5 is a rational number.

That is , we can find the coprime a and b where b≠0 such that :-

3+√5 = a/b

Therefore, 3+a/b = √5

Rearranging the equation , we get √5 = 3-a/b = 3b-a/b

since , a and b are Integers , we get 3-a/b is a rational , and so √5 is rational.

but this contradicts the fact that √5 is irrational.

this contradiction has arisen because of our incorrect exception that 3+√5 is a rational.

so , we conclude that 3+√5 is a Irrational number.

Step-by-step explanation:

i hope this answer help you.

Answer 2

Refer to attachment for da incórrect answer .