Math, asked by TheDarkQueen, 9 months ago

Prove that 3+/5 is irrational

Answers

Answered by Anonymous
4

\huge\mathfrak\blue{Answer:}

Given:

  • Given a number 3 + \sqrt{5}

To Prove:

  • We have to prove that given number is irrational

Solution:

Let us assume 3 +  \sqrt{5} be a rational number

So it can written in the form of a/b where a and B are non zero co-prime numbers

 =  > 3 +  \sqrt{5}  =  \dfrac{a}{b}

 =  >  \sqrt{5}  =   \dfrac{a - 3b}{ b}

We know that  \sqrt{5} is an irrational number

A Rational number can never be be equal to an irrational number.

Therefore our assumption was wrong

Hence 3 +  \sqrt{5} is an irrational number

_____________________________

NOTE:

  • This method of proving rational number is known as Contradiction method
  • In this method first we contradict a fact and later proves that our assumption was wrong
Answered by angelgirl57
4

Answer:

3+/5 is a irrational number because in this number there is + sign and then / this sign so it is a irrational number...

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