prove that (3+√5) is irrational
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Answer:
3+ 5= ba[Here a and b are co-prime numbers]5 =[( ba )−3]5 =[( ba−3b)]
Here, [( ba−3b )] is a rational number.
But we know that
5is an irrational number.
So, [( ba−3b )] is also a irrational number.
So, our assumption is wrong.
3+ root 5 is an irrational number.
Step-by-step explanation:
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Answer:
prove that (3+√5) is irrational in photo you can see the answer
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