Math, asked by reksx67890, 1 day ago

prove that ✓3+✓5 is irrational​

Answers

Answered by bochan16
0

Step-by-step explanation:

Method 1 -

Let

\sqrt{3} + \sqrt{5}  = x = rational\\Thus, \sqrt{3} = x - \sqrt{5}  = rational

But

\sqrt{3}  = Irrational

Hence Proved,

\sqrt{3} + \sqrt{5}  = irrational

Method 2 -

\\\sqrt{3} + \sqrt{5} = x\ = rational \\\ Thus , (\sqrt{3} + \sqrt{5} )^{2} = x^{2} = rational\\=>     8 + 2\sqrt{15} =x^{2} = rational \\=>      \sqrt{15}  = \frac{x^{2}  -8 }{2}  = rational\\\\

But

\sqrt{15} = irrational

Thus this is a contradiction .

Hence proved ,

\sqrt{3} + \sqrt{5}  = irrational

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