Question

prove that (√3*5power-3/3√3-1 √5)*√3*5power6=3/5​

Answer 1

Step-by-step explanation:

The floor function (also known as the greatest integer function) \lfloor\cdot\rfloor: \mathbb{R} \to \mathbb{Z}⌊⋅⌋:R→Z of a real number xx denotes the greatest integer less than or equal to xx. For example, \lfloor 5\rfloor=5, ~\lfloor 6.359\rfloor =6, ~\left\lfloor \sqrt{7}\right\rfloor=2, ~\lfloor \pi\rfloor = 3, ~\lfloor -13.42\rfloor = -14.⌊5⌋=5, ⌊6.359⌋=6, ⌊

7

⌋=2, ⌊π⌋=3, ⌊−13.42⌋=−14.

In general, \lfloor x \rfloor⌊x⌋ is the unique integer satisfying \lfloor x\rfloor\le x<\lfloor x\rfloor +1⌊x⌋≤x<⌊x⌋+1.

Let \{x\}{x} denote the fractional part of xx with 0\le \{x\}<10≤{x}<1, for example, \{2.137\}=0.137.{2.137}=0.137. Then x=\lfloor x\rfloor+\{x\}x=⌊x⌋+{x} for any real number xx. For example, 3.1416=3+0.1416,3.1416=3+0.1416, with \lfloor x\rfloor =3⌊x⌋=3 and \{x\}=0.1416{x}=0.1416.

The floor function is at every integer.

The floor function is discontinuous at every integer