prove that (3+5w+3w)^6=64
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Answer:
Given,
(3 + 3w + 5w^{2})6w
= [ 3(1 + w) + 5w ^{2}]6w
= [3w^{2} + 5w^{2}]6w
= [8w^{2}]6w \\ \\ = 48w^{3}
=24
Note 1. \ \ 1 + w + w^{2} = 0 \\ \\ 2. \ \ w^{3} = 1
Step-by-step explanation:
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