Question

prove that 3-7√5 is irrational​

Answer 1

Answer:  we know that 3 is rational and 7root 5 is irrational so rational +irrational = irrational

Step-by-step explanation: let 3+7root5 is a rational number

a/b=3+7root5

7root5=a/b-3

root5=a/7b-3

root5=a-21b/7b

in LHSroot5 is irrational but in RHS a-21b/7b is rational number so our acceptation went wrong so 3+7root5 is irrational number

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