Question

Prove that 3√7 - 5 is irrational.

Answer 1

Answer:

3-5 3-5 3-5 3-5 3-53-53-5

Answer 2

Step-by-step explanation:

Let us assume that 3√7 -5 is a rational no.

i.e., 3√7 -5 = p/q (where q≠0)

Therefore,

3√7 = p/q +5

3√7 = p+5q/q

√7 = p+5q/3q

Here, p, 5q and 3q are rational numbers and integers. But we know that , √7 is an irrational no.

This is contradiction.

Hence, proved that 3√7 -5 is an irrational no.

Pls, Pls... mark me as brainliest..!