Question

prove that ³√7 is an irrational.​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

prove that ³√7 is an irrational.

Step-by-step explanation:

Let √ means cubth root.

Assume that √7 is rational and hence = p/q

Also (p/q) is reduced to the lowest form.

p = q * √7

Since p is multiple of q , q divides P .

Tgat is p = nq where n is an integer.

7^ (1/3) = p/q = nq/q

So p/q is not reduced to the lowest form .

This leads to contradiction.

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