Math, asked by jashan07, 1 year ago

prove that 3 +√7 is an irrational number​

Answers

Answered by Anonymous
2

\large{\underline{\boxed{ Answer}}}

Let 3 + √7 be a rational number then it can be expressed in the form of P/q where p and q are co-prime and q ≠ 0.

Then,

\implies 3 +  \sqrt{7}  =  \frac{p}{q}

transfer 3 on R. H. S

\implies  \sqrt{7}  =  \frac{p}{3q}

we know that √7 is an irrational number.

also,every operation of a rational is itself a rational number.

Then, division of rational is also rational number.

but L. H. S is an irrational and R. H. S is rational

Therefore, L. H. S ≠ R. H. S

hence,our assumption is wrong 3+√7 is an irrational number

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