Prove that√3 -7 is an irrational number
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Let the √3 is rational so it can be written in the form of p/q where p and q are co prime
√3=a/b
squaring on both sides we get
3=a²/b²
3b²=a²
hence a²divide 3b² so it also divide 3b
now le a =3c
3b²=(3c)²
3b²= 9c²
hence 3b² divide 9c² and hence 9c
thus a and b are not co prime
hence √3 is irrational❤️
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Answer:
Let the √3 is rational so it can be written in the form of p/q where p and q are co prime
√3=a/b
squaring on both sides we get
3=a²/b²
3b²=a²
hence a²divide 3b² so it also divide 3b
now le a =3c
3b²=(3c)²
3b²= 9c²
hence 3b² divide 9c² and hence 9c
thus a and b are not co prime
hence √3 is irrational
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