prove that 3√7 is irrational
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Answered by
1
HERE IS YOUR ANSWER--
Step-by-step explanation:
LET 3/(rooot7) BE RATIONAL,
SO , WE CAN SAY THAT
3×(root7)/7IS RATIONAL
IT IS OF THE FORM
PN/Q , WHERE P/Q IS RATIONAL,
SO N SHOULD ALSO BE RATIONAL
BUT WE KNOW THAT root7 IS IRRATIONAL,
SO,
IT CONTRADICTS OUR ASSUMPTIONS
HENCE,
3/(root7) IS IRRATIONAL,
HENCE PROVED
CHEERS
Answered by
1
Hii friend,If possible , let 3✓7 be rational Number. Then 3✓7 is rational , 1/3 is rational.=> (1/3 × 3✓7) is rational.
contradiction with field axiom 1 of the reals - the axiom that the operation of addition is closed, that is ∀x,y∈R x+y∈R. therefore 3+root7 is irrational. ... All you need to know is that root 7 is irrational, because the definition of irrational is that it cannot be expressed as a fraction.
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