Question

Prove that (3^a/3^b)^a+b x (3^b/3^c)^b+c x (3^c/3^a)^c+a=1​

Answer 1

Answer:

{3}^{(a - b)(a - b)} x {3}^{(b - c)(b + c)} x {3}^{(c - a)(c + a)}

3^(A2 - b2) x 3 ^(b2 - C2) x 3^(c2-a2)

3^a2/ 3^b2 x 3^b2/ 3^c2 x 3^c2 / 3^a2

by cancellinga all we get =1

thanks...